The dot matrix animation display, in the final analysis, is to take multiple pictures and take pictures. Using the program algorithm to intelligently switch pictures, multiple pictures are combined to become an animation. We see cartoons, games, etc. Their basic principles are also the same.
In the previous section we learned how to draw a cocoon on a dot matrix. Sometimes we want these displays to be dynamic, not static. There isn't much knowledge about the dot matrix itself. The main point is the programming algorithm to solve the problem. For example, we now want to let the dot matrix display an I ⤠U animation. First of all, we need to draw this graph with the modulus software, as shown in Figure 7-10.
Figure 7-10 Up and down horizontal die movement
There are 40 lines in this picture. Every 8 lines form a dot matrix picture, and a new picture appears each time you move one line up. A total of 32 pictures are formed.
Use a variable index to represent the starting position of each picture. Each time from the beginning of the index, 8 lines represent the current picture, 250ms change a picture, and then keep the dynamic refresh, so that the picture becomes an animation Now. First of all, we need to horizontally model the displayed image. Although this is 32 images, since each of our images is continuous with the next line, the actual modulus value can be completed with only 40 bytes. Take a look at the program.
#include
Sbit ADDR0 = P1^0;
Sbit ADDR1 = P1^1;
Sbit ADDR2 = P1^2;
Sbit ADDR3 = P1^3;
Sbit ENLED = P1^4;
Unsigned char code image[] = {// The font table of the picture
0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF,
0xC3, 0xE7, 0xE7, 0xE7, 0xE7, 0xE7, 0xC3, 0xFF,
0x99, 0x00, 0x00, 0x00, 0x81, 0xC3, 0xE7, 0xFF,
0x99, 0x99, 0x99, 0x99, 0x99, 0x81, 0xC3, 0xFF,
0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF
};
Void main(){
EA = 1; //Enable total interrupt
ENLED = 0; //Enable U4, select LED dot matrix
ADDR3 = 0;
TMOD = 0x01; // Set T0 to mode 1
TH0 = 0xFC; // Initial value 0xFC67 for T0, timing 1ms
TL0 = 0x67;
ET0 = 1; //Enable T0 interrupt
TR0 = 1; //Start T0
While (1);
}
/* Timer 0 interrupt service function */
Void InterruptTimer0() interrupt 1{
Static unsigned char i = 0; // dynamic scan index
Static unsigned char tmr = 0; //250ms software timer
Static unsigned char index = 0; //image refresh index
TH0 = 0xFC; //Reload initial value
TL0 = 0x67;
//The following code completes dynamic refresh of LED dot matrix
P0 = 0xFF; //display blanking
Switch (i){
Case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=image[index+0]; break;
Case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=image[index+1]; break;
Case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=image[index+2]; break;
Case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=image[index+3]; break;
Case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=image[index+4]; break;
Case 5: ADDR2=1; ADDR1=0; ADDR0=1; i++; P0=image[index+5]; break;
Case 6: ADDR2=1; ADDR1=1; ADDR0=0; i++; P0=image[index+6]; break;
Case 7: ADDR2=1; ADDR1=1; ADDR0=1; i=0; P0=image[index+7]; break;
Default: break;
}
//The following code completes changing one frame every 250ms
Tmr++;
If (tmr >= 250) { // change the picture index when reaching 250ms
Tmr = 0;
Index++;
If (index >= 32){ //Return to zero after the picture index reaches 32
Index = 0;
}
}
}
We downloaded this program to the MCU to see the effect. An animation of I ⤠U that has been moving upwards appeared. Which dare to say that our engineering students do not understand romance? Need to use any roses to please girlfriend? There is no technical content, to play with high-tech, huh, huh.
Of course, don't be happy. Learn to continue. Moving up the animation I wrote it out. The animations that move down should be completed independently. Don't be lazy. Be sure to write code to debug the code. At first glance, only knowledge can be understood, and competence is cultivated in the practice of actually writing code and debugging code.
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